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Old October 26th, 2005, 23:25   #9
mcguyver's Avatar
Join Date: Aug 2005
Location: Northern Alberta
i checked the cfc website and it is both velocity and energy for airguns. so where did i miss the .5? if its .5joules = kg x (m/s)^2 then my numbers will be half the actual. if it's joules = .5 kg x (m/s)^2 then my numbers are double (not likely). could you type me out your formula as the one in my 1990 u of a text says joules = kg x (m/s)^2 and i'm too old to remember from that long ago. thanx.
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