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Old March 6th, 2010, 12:43   #2
L473ncy's Avatar
Join Date: Oct 2004
Location: 11-30-24-1W5
I'm a bit rusty on my physics but essentially Voltage is the ability to "push" current. Higher voltage means that you get more "umph". So as it stands higher voltage translates into a higher ROF.

Amperes on the other hand (in this case milliampere*hours) is the amount of charge or "juice" you have. The unit derives from some weird measure that I forget, it has something to do with "Coulombs" though (a unit of electric charge). Like I said it's been a while since I last took physics.

So take these examples:

8.4V-1400 mAh battery: you shoot 1200 BB's (assuming that you get 1BB per mAh) that means you only have about 200 mAh (worth of "juice") in the battery at the end of the day. When you have no more (or very little) what happens? Lets say you do one last round and shoot your last 200 BB's. You have no "juice", there isn't any charge or "juice" in the battery pack that can be used to propel a BB.

Now take that same battery but instead add another cell to it turning it into a 9.6V-1400 mAh battery. Notice how it's still 1400 mAh? You didn't increase the amount of juice you have in your battery pack BUT you increased the voltage by adding another cell. Why? Well, the battery is setup in "series". Adding cells adds to voltage, a disadvantage being if one cell fails (not very likely) the pack is unusable until you replace or repair the pack or cell, just like older christmas lights where you had to find which bulb burnt out or it wouldn't work. These days christmas lights are setup in parallel. Anyways, you didn't increase the capacity of the pack to hold a charge rather you increased the "umph", the "push" of electricity to the motor/internals. As a result you notice the trigger response is "faster" as well you get a ROF increase because there is now more juice to pull the spring back faster.
ಠ_ಠLess QQ more Pew Pew

Last edited by L473ncy; March 6th, 2010 at 12:45..
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